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(C) In humans,the trait for curly hair is dominant $(C)$ and the trait for straight hair is recessive $(c)$.Assuming the mother is homozygous dominant

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$4:4$

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(C) In humans,the trait for curly hair is dominant $(C)$ and the trait for straight hair is recessive $(c)$.Assuming the mother is homozygous dominant $(CC)$ and the father is homozygous recessive $(cc)$,all offspring will be heterozygous $(Cc)$ and exhibit curly hair.However,if the mother is heterozygous $(Cc)$ and the father is homozygous recessive $(cc)$,the cross is $Cc 	imes cc$.The resulting genotypes are $Cc$ (curly) and $cc$ (straight) in a $1:1$ ratio.For $8$ children,the expected distribution is $4$ curly-haired and $4$ straight-haired,resulting in a ratio of $4:4$.

$S.No$	Cross	Result
$I.$ Strain $1 \times gg$	All wild type
$II.$ Strain $2 \times gg$	$1$ wild type $: 1$ ebony
$III.$ Strain $3 \times gg$	All ebony
$IV.$ Strain $4 \times Gg$	$3$ wild type $: 1$ ebony

As a result of the marriage between a curly-haired mother and a straight-haired father,$8$ children are born. What is the expected ratio of curly-haired to straight-haired children?

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