(D) According to the law of conservation of mechanical energy,the total mechanical energy at point $A$ is equal to the total mechanical energy at poin

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(D) According to the law of conservation of mechanical energy,the total mechanical energy at point $A$ is equal to the total mechanical energy at point $B$.$E_A = E_B$$PE_A + KE_A = PE_B + KE_B$Given that the particle starts from rest at $A$,$KE_A = 0$.$mgh_A + 0 = mgh_B + \frac{1}{2}mv^2$$gh_A = gh_B + \frac{1}{2}v^2$$v^2 = 2g(h_A - h_B)$Substituting the given values: $g = 10 \ m/s^2$,$h_A = 10 \ m$,$h_B = 5 \ m$.$v^2 = 2 \times 10 \times (10 - 5)$$v^2 = 20 \times 5 = 100$$v = \sqrt{100} = 10 \ m/s$Therefore,the value of $x$ is $10$.

Class 11 Physics Work, Energy, Power and Collision Work Energy Theorem and Conservation of Mechanical Energy

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As shown in the figure,a particle of mass $10 \ kg$ is placed at a point $A$. When the particle is slightly displaced to its right,it starts moving and reaches the point $B$. The speed of the particle at $B$ is $x \ m/s$. (Take $g = 10 \ m/s^2$). The value of $x$ to the nearest integer is:

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A
$5$
B
$8$
C
$12$
D
$10$

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As shown in the figure,a particle of mass $10 \ kg$ is placed at a point $A$. When the particle is slightly displaced to its right,it starts moving and reaches the point $B$. The speed of the particle at $B$ is $x \ m/s$. (Take $g = 10 \ m/s^2$). The value of $x$ to the nearest integer is:

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