As shown in the figure, charges +q, +q, -q an | vedclass

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Question

(D) Point '$A$' is at a distance $l$ from the top $+q$ charge and the bottom $+q$ charge.The distance from point '$A$' to both $-q$ charges is $\sqrt{

Vedclass · Accepted Answer

$\frac{2kq}{l}[1-\frac{1}{\sqrt{5}}]$

Vedclass · Answer

(D) Point '$A$' is at a distance $l$ from the top $+q$ charge and the bottom $+q$ charge.The distance from point '$A$' to both $-q$ charges is $\sqrt{(2l)^2 + l^2} = \sqrt{4l^2 + l^2} = \sqrt{5l^2} = l\sqrt{5}$.The electric potential $V$ at point '$A$' due to all four charges is given by the sum of potentials from each charge:$V_A = k(\frac{q}{l} + \frac{q}{l} - \frac{q}{l\sqrt{5}} - \frac{q}{l\sqrt{5}})$$V_A = k(\frac{2q}{l} - \frac{2q}{l\sqrt{5}})$$V_A = \frac{2kq}{l}(1 - \frac{1}{\sqrt{5}})$Therefore, option $(D)$ is correct.

As shown in the figure, charges $+q, +q, -q$ and $-q$ are placed on the vertices of a square, each side length is $2l$. The electric potential at the mid-point '$A$' of the charges $+q$ and $+q$ is . . . . . . .

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