(D) In group $14$ (or $IVA$),the stability of the $+2$ oxidation state increases down the group due to the inert pair effect. $Pb$ is at the bottom of

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(D) In group $14$ (or $IVA$),the stability of the $+2$ oxidation state increases down the group due to the inert pair effect. $Pb$ is at the bottom of the group,so $Pb^{2+}$ is much more stable than $Pb^{4+}$. $I^-$ is a mild reducing agent and cannot oxidize $Pb^{2+}$ to $Pb^{4+}$. Therefore,$PbI_4$ is not a stable compound. Both the Assertion and the Reason are incorrect.

Class 11 Chemistry p-Block Elements (Class 11)Carbon family

Medium

Assertion : $PbI_4$ is a stable compound.
Reason : Iodide stabilizes higher oxidation state.

AIIMS 2003 All AIIMS

A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

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Given below are two statements:
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DifficultJEE MAIN 2024

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In the following reaction,assign the correct category for the underlined atom based on the product of complete hydrolysis at $R.T.$:
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Provide information about silicon compounds (silicates).

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Assertion : $PbI_4$ is a stable compound.Reason : Iodide stabilizes higher oxidation state.

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In the following reaction,assign the correct category for the underlined atom based on the product of complete hydrolysis at $R.T.$:$\underline{C}O_2 + H_2O \longrightarrow H_2CO_3$

Provide information about silicon compounds (silicates).

Which one of the following is used as a refrigerant for ice-cream and frozen foods?

Give one method for industrial preparation and one for laboratory preparation of $CO$ and $CO_{2}$ each.

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Assertion : $PbI_4$ is a stable compound.
Reason : Iodide stabilizes higher oxidation state.

In the following reaction,assign the correct category for the underlined atom based on the product of complete hydrolysis at $R.T.$:
$\underline{C}O_2 + H_2O \longrightarrow H_2CO_3$