(C) For a deuteron: charge $q_d = e$,mass $m_d = 2m_p = 2m$.For an $\alpha -$ particle: charge $q_{\alpha} = 2e$,mass $m_{\alpha} = 4m_p = 4m$.The for

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(C) For a deuteron: charge $q_d = e$,mass $m_d = 2m_p = 2m$.For an $\alpha -$ particle: charge $q_{\alpha} = 2e$,mass $m_{\alpha} = 4m_p = 4m$.The force on a charge $q$ in an electric field $E$ is given by $F = qE$.Thus,$F_1 = eE$ and $F_2 = 2eE$. Since $F_1 \neq F_2$,the Reason is incorrect.Now,calculating accelerations using $a = F/m$:$a_1 = F_1 / m_d = (eE) / (2m) = eE / 2m$.$a_2 = F_2 / m_{\alpha} = (2eE) / (4m) = eE / 2m$.Since $a_1 = a_2$,the Assertion is correct.Therefore,the Assertion is correct but the Reason is incorrect.

Class 12 Physics Electric Charges and Fields Motion of Charge particle in Electric filed

Medium

Assertion : $A$ deuteron and an $\alpha -$ particle are placed in an electric field. If $F_1$ and $F_2$ are the forces acting on them and $a_1$ and $a_2$ are their accelerations respectively,then $a_1 = a_2$.
Reason : Forces will be same in an electric field.

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A
If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
B
If both Assertion and Reason are correct,but Reason is not the correct explanation of Assertion.
C
If Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

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Electric Charges and Fields

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Motion of Charge particle in Electric filed

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$A$ charged particle with charge $q$ and mass $m$ starts with an initial kinetic energy $K$ at the centre of a uniformly charged spherical region of total charge $Q$ and radius $R$. Charges $q$ and $Q$ have opposite signs. The spherically charged region is not free to move and kinetic energy $K$ is just sufficient for the charged particle to reach the boundary of the spherical charge. How much time does it take the particle to reach the boundary of the region?

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An electron enters an electric field of intensity $3200 \ V/m$ perpendicular to the field with a velocity of $4 \times 10^7 \ m/s$. If it travels a horizontal distance of $0.10 \ m$,then its deflection from its path is ........ $mm$.

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An electron experiences a force equal to its weight when placed in an electric field. The intensity of the field will be

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The electric field at a point is given by $\vec E = E_0 \hat i \, V/m$. $A$ particle of charge $+q_0$ moves from point $A(0, a)$ to $B(a, 0)$ along a circular path as shown in the figure. Find the work done by the electric field in this motion.

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In a uniform electric field of $E = 1 \times 10^{4} \text{ N C}^{-1}$,an electron is accelerated from rest. The velocity of the electron when it has travelled a distance of $2 \times 10^{-2} \text{ m}$ is nearly (given $\frac{e}{m} \text{ of electron } \approx 1.8 \times 10^{11} \text{ C kg}^{-1}$):

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Assertion : $A$ deuteron and an $\alpha -$ particle are placed in an electric field. If $F_1$ and $F_2$ are the forces acting on them and $a_1$ and $a_2$ are their accelerations respectively,then $a_1 = a_2$.Reason : Forces will be same in an electric field.

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An electron enters an electric field of intensity $3200 \ V/m$ perpendicular to the field with a velocity of $4 \times 10^7 \ m/s$. If it travels a horizontal distance of $0.10 \ m$,then its deflection from its path is ........ $mm$.

An electron experiences a force equal to its weight when placed in an electric field. The intensity of the field will be

The electric field at a point is given by $\vec E = E_0 \hat i \, V/m$. $A$ particle of charge $+q_0$ moves from point $A(0, a)$ to $B(a, 0)$ along a circular path as shown in the figure. Find the work done by the electric field in this motion.

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Assertion : $A$ deuteron and an $\alpha -$ particle are placed in an electric field. If $F_1$ and $F_2$ are the forces acting on them and $a_1$ and $a_2$ are their accelerations respectively,then $a_1 = a_2$.
Reason : Forces will be same in an electric field.