Assertion : Angular momentum of an electron i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The assertion states that the angular momentum of an electron in an orbit is given by $mvr = \frac{nh}{2\pi}$,which is a fundamental postulate of

Vedclass · Accepted Answer

If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.

Vedclass · Answer

(B) The assertion states that the angular momentum of an electron in an orbit is given by $mvr = \frac{nh}{2\pi}$,which is a fundamental postulate of the Bohr model of the atom. This statement is correct.The reason states that the principal quantum number,$n$,can have any integral value $(n = 1, 2, 3, \dots)$. This is also a correct statement regarding the definition of the principal quantum number.However,the fact that $n$ can take any integral value is not the reason why the angular momentum is quantized as $\frac{nh}{2\pi}$. The quantization of angular momentum is a separate postulate derived from the wave nature of the electron. Therefore,the reason is not the correct explanation of the assertion.

Assertion : Angular momentum of an electron in any orbit is given by angular momentum $= \frac{nh}{2\pi}$,where $n$ is the principal quantum number.
Reason : The principal quantum number,$n$,can have any integral value.

Similar Questions

For a $H$ atom,the energy transition from $n = 1$ to $n = 2$ is $10.2 \ eV$. What will be the energy for the same transition in $Be^{3+}$ ion?

The relation between the stopping potential $(V_0)$ and frequency $(v)$ is correctly represented in $[\phi = \text{Work function}]$

In the atomic spectrum of hydrogen,the series of lines observed in the visible region is:

The energy required for the ionization of an excited hydrogen atom would be (in $eV$)-

In Bohr's model,the atomic radius of the first orbit is $\gamma$. The radius of the $3^{rd}$ orbit is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion : Angular momentum of an electron in any orbit is given by angular momentum $= \frac{nh}{2\pi}$,where $n$ is the principal quantum number.Reason : The principal quantum number,$n$,can have any integral value.