Assertion : Both Be and Al can form complexes | vedclass

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Question

(A) The assertion is correct because $Be$ can expand its coordination number up to $4$ due to the presence of only $s$ and $p$ orbitals in its valence

Vedclass · Accepted Answer

If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

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(A) The assertion is correct because $Be$ can expand its coordination number up to $4$ due to the presence of only $s$ and $p$ orbitals in its valence shell $(n=2)$.$Al$ can expand its coordination number to $6$ because it has vacant $3d$ orbitals in its valence shell $(n=3)$.Since $Be$ lacks vacant $d-$ orbitals,it cannot form $BeF_6^{3-}$,which would require a coordination number of $6$.Thus,the reason correctly explains the assertion.

Assertion : Both $Be$ and $Al$ can form complexes such as $BeF_4^{2-}$ and $AlF_6^{3-}$ respectively,$BeF_6^{3-}$ is not formed.
Reason : In case of $Be$,no vacant $d-$ orbitals are present in its outermost shell.

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Assertion : Both $Be$ and $Al$ can form complexes such as $BeF_4^{2-}$ and $AlF_6^{3-}$ respectively,$BeF_6^{3-}$ is not formed.Reason : In case of $Be$,no vacant $d-$ orbitals are present in its outermost shell.