Assertion : Equivalent weight of a base $= \frac{\text{Molecular weight}}{\text{Acidity}}$
Reason : Acidity is the number of replaceable hydrogen atoms in one molecule of the base.
Reason : Acidity is the number of replaceable hydrogen atoms in one molecule of the base.
- AIf both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
- BIf both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
- CIf the Assertion is correct but Reason is incorrect.
- DIf both the Assertion and Reason are incorrect.
Explore More
Similar Questions
$A$ mixture of $1.65 \times 10^{21}$ molecules of $X$ and $1.85 \times 10^{21}$ molecules of $Y$ weighs $0.688 \ g$. If the molecular mass of $Y$ is $187 \ g/mol$,what is the molecular mass of $X$?
Medium
View SolutionWhat will be the mass of one $^{12}C$ atom in $g$?
Difficult
View SolutionIf $M_1$ and $M_2$ are the molecular weights of $Al(OH)_3$ and $H_3PO_3$ respectively,find their equivalent weights in the following reaction:
$Al(OH)_3 + 2H_3PO_3 \to Al(OH)(H_2PO_3)_2 + 2H_2O$
$Al(OH)_3 + 2H_3PO_3 \to Al(OH)(H_2PO_3)_2 + 2H_2O$
Difficult
View Solution$H_2SeO_4 + NaOH \to NaHSeO_4$; $E.W.$ of $H_2SeO_4 = E_1$
$H_2SeO_4 + 2NaOH \to Na_2SeO_4$; $E.W.$ of $H_2SeO_4 = E_2$
What is the relation between $E_1$ and $E_2$?
$H_2SeO_4 + 2NaOH \to Na_2SeO_4$; $E.W.$ of $H_2SeO_4 = E_2$
What is the relation between $E_1$ and $E_2$?
Difficult
View SolutionCalculate the molecular mass of a glucose $C_{6}H_{12}O_{6}$ molecule.
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo