(D) Specific conductance (conductivity,$\kappa$) is defined as the conductance of $1 \ cm^3$ of the solution.On increasing dilution,the number of ions

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(D) Specific conductance (conductivity,$\kappa$) is defined as the conductance of $1 \ cm^3$ of the solution.On increasing dilution,the number of ions per unit volume decreases,which leads to a decrease in specific conductance.Therefore,the Assertion is incorrect.Although the degree of ionization and ionic mobility increase with dilution,the Assertion itself is false,making the correct choice $D$.

Class 12 Chemistry Electrochemistry Conductor and Conductance and Cell constant

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Assertion : On increasing dilution,the specific conductance keeps on increasing.
Reason : On increasing dilution,the degree of ionization of a weak electrolyte increases and the mobility of ions also increases.

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A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

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Given below is the plot of the molar conductivity vs $\sqrt{concentration}$ for $KCl$ in aqueous solution. If,for the higher concentration of $KCl$ solution,the resistance of the conductivity cell is $100 \ \Omega$,then the resistance of the same cell with the dilute solution is '$x$' $\Omega$. The value of $x$ is $............$ ($Nearest$ $integer$)

DifficultJEE MAIN 2025

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At $25\,^{\circ}C$,the molar conductivity at infinite dilution for electrolytes $KOH$,$KCl$ and $BaCl_2$ are $248 \times 10^{-4}$,$126 \times 10^{-4}$ and $280 \times 10^{-4}\,S\,m^2\,mol^{-1}$ respectively. Calculate $\Lambda _m^{\infty}$ for $Ba(OH)_2$ (in $S\,m^2\,mol^{-1}$).

Medium

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The specific conductivity of a normal solution of $KCl$ at $25 \, ^oC$ is $0.002765 \, S \, cm^{-1}$. If the resistance of the cell is $400 \, \Omega$,what is the cell constant (in $cm^{-1}$)?

Easy

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The specific conductivity of a $0.01 \ M$ salt solution is $1.061 \times 10^{-4} \ S \ cm^{-1}$. The molar conductivity of this solution is:

Easy

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The limiting molar conductivities $\wedge ^0$ for $NaCl$,$KBr$,and $KCl$ are $126$,$152$,and $150 \ S \ cm^2 \ mol^{-1}$ respectively. The $\wedge ^0$ for $NaBr$ is ............ $S \ cm^2 \ mol^{-1}$.

MediumAIEEE 2004

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Assertion : On increasing dilution,the specific conductance keeps on increasing.Reason : On increasing dilution,the degree of ionization of a weak electrolyte increases and the mobility of ions also increases.

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At $25\,^{\circ}C$,the molar conductivity at infinite dilution for electrolytes $KOH$,$KCl$ and $BaCl_2$ are $248 \times 10^{-4}$,$126 \times 10^{-4}$ and $280 \times 10^{-4}\,S\,m^2\,mol^{-1}$ respectively. Calculate $\Lambda _m^{\infty}$ for $Ba(OH)_2$ (in $S\,m^2\,mol^{-1}$).

The specific conductivity of a normal solution of $KCl$ at $25 \, ^oC$ is $0.002765 \, S \, cm^{-1}$. If the resistance of the cell is $400 \, \Omega$,what is the cell constant (in $cm^{-1}$)?

The specific conductivity of a $0.01 \ M$ salt solution is $1.061 \times 10^{-4} \ S \ cm^{-1}$. The molar conductivity of this solution is:

The limiting molar conductivities $\wedge ^0$ for $NaCl$,$KBr$,and $KCl$ are $126$,$152$,and $150 \ S \ cm^2 \ mol^{-1}$ respectively. The $\wedge ^0$ for $NaBr$ is ............ $S \ cm^2 \ mol^{-1}$.

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Assertion : On increasing dilution,the specific conductance keeps on increasing.
Reason : On increasing dilution,the degree of ionization of a weak electrolyte increases and the mobility of ions also increases.