Class 11BiologyExcretory Products and their EliminationMix Examples- Excretory Products and their Elimination
MediumAssertion : Secreting hypotonic urine is effective in reducing urinary loss of water.
Reason : Hypotonic urine is more concentrated and higher in osmotic pressure than the blood.
Reason : Hypotonic urine is more concentrated and higher in osmotic pressure than the blood.
- AIf both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
- BIf both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
- CIf the Assertion is correct but Reason is incorrect.
- DIf both the Assertion and Reason are incorrect.
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Similar Questions
Match the items of column $I$ with those of column $II$:
Column $I$ Column $II$ $(a)$ Ammonotelism $(i)$ Birds $(b)$ Bowman's capsule $(ii)$ Water reabsorption $(c)$ Micturition $(iii)$ Bony fish $(d)$ Uricotelism $(iv)$ Urinary bladder $(e)$ $ADH$ $(v)$ Renal tubule
| Column $I$ | Column $II$ |
| $(a)$ Ammonotelism | $(i)$ Birds |
| $(b)$ Bowman's capsule | $(ii)$ Water reabsorption |
| $(c)$ Micturition | $(iii)$ Bony fish |
| $(d)$ Uricotelism | $(iv)$ Urinary bladder |
| $(e)$ $ADH$ | $(v)$ Renal tubule |
Easy
View SolutionIdentify the true statements and choose the correct option accordingly.
$I.$ Blood vessel leading to the glomerulus is called efferent arteriole.
$II.$ Vasa-recta,peritubular capillaries and glomerulus,all have blood.
$III.$ Cortical nephrons have highly reduced vasa-recta.
$IV.$ Vasa-recta runs parallel to the Henle's loop in the juxta-medullary nephron.
$I.$ Blood vessel leading to the glomerulus is called efferent arteriole.
$II.$ Vasa-recta,peritubular capillaries and glomerulus,all have blood.
$III.$ Cortical nephrons have highly reduced vasa-recta.
$IV.$ Vasa-recta runs parallel to the Henle's loop in the juxta-medullary nephron.
Medium
View SolutionStale urine smells like ammonia because
Medium
View SolutionExplain briefly,micturition and disorders of the excretory system.
Easy
View SolutionThe volume of the filtrate per day is $X$ liters and the volume of urine released per day is $Y$ liters. It means about $Z$ $\%$ of the filtrate is reabsorbed by the process of reabsorption.
Medium
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