(D) The molar mass of water vapor $(H_2O)$ is $18 \ g/mol$,while the average molar mass of dry air (mostly $N_2$ and $O_2$) is approximately $29 \ g/m

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

If the Assertion is incorrect but the Reason is correct.

(D) The molar mass of water vapor $(H_2O)$ is $18 \ g/mol$,while the average molar mass of dry air (mostly $N_2$ and $O_2$) is approximately $29 \ g/mol$.Since water vapor replaces heavier air molecules,wet air is actually lighter than dry air,making the Assertion incorrect.The density of dry air is much lower than the density of liquid water,making the Reason also incorrect.

Class 11 Chemistry States of Matter Mix Examples- States of Matter

Medium

Assertion : Wet air is heavier than dry air.
Reason : The density of dry air is more than density of water.

AIIMS 1999 All AIIMS

A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If the Assertion is incorrect but the Reason is correct.

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

States of Matter

Subtopic

Mix Examples- States of Matter

Previous Year

AIIMS 1999 Paper All AIIMS years →

Equal volumes of monoatomic and diatomic gases at same initial temperature and pressure are mixed. The ratio of specific heats of the mixture $({C_p}/{C_v})$ will be

Medium

View Solution

Two flasks $A$ and $B$ have equal volumes. $A$ is maintained at $300 \ K$ and $B$ at $600 \ K$. Equal masses of $H_2$ and $CO_2$ are taken in flasks $A$ and $B$ respectively. Find the ratio of total $K.E.$ of gases in flask $A$ to that of $B$.

EasyAP EAMCET 2021

View Solution

$80 \ mL$ of $O_2$ takes $2 \ minute$ to pass through a hole. What volume of $SO_2$ will pass through the same hole in $3 \ minute$?

Difficult

View Solution

For a liquid,the normal boiling point is $-173\,^{\circ}C$. At $2\ atm$ pressure,its boiling point should be nearly ......... $^{\circ}C$. (Given: $\Delta H_{vap} = 200\ cal/mol$,$R = 2\ cal/mol\cdot K$,$\ln 2 = 0.7$)

Medium

View Solution

$1 \text{ mole}$ of gas $A$ and $1 \text{ mole}$ of gas $B$ at $27^{\circ} C$ were pumped into a $24.6 \ L$ volume pre-evacuated isolated flask. The catalyst coated inside the flask catalyses the following reaction $A_{(g)} + B_{(g)} \longrightarrow 2 D_{(g)}$. The kinetic energy of $D$ is $98.03 \ L \ atm$. Calculate the pressure realized at the end of the reaction. (in $atm$)

MediumTS EAMCET 2018

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Assertion : Wet air is heavier than dry air.Reason : The density of dry air is more than density of water.

Similar Questions

Equal volumes of monoatomic and diatomic gases at same initial temperature and pressure are mixed. The ratio of specific heats of the mixture $({C_p}/{C_v})$ will be

Two flasks $A$ and $B$ have equal volumes. $A$ is maintained at $300 \ K$ and $B$ at $600 \ K$. Equal masses of $H_2$ and $CO_2$ are taken in flasks $A$ and $B$ respectively. Find the ratio of total $K.E.$ of gases in flask $A$ to that of $B$.

$80 \ mL$ of $O_2$ takes $2 \ minute$ to pass through a hole. What volume of $SO_2$ will pass through the same hole in $3 \ minute$?

For a liquid,the normal boiling point is $-173\,^{\circ}C$. At $2\ atm$ pressure,its boiling point should be nearly ......... $^{\circ}C$. (Given: $\Delta H_{vap} = 200\ cal/mol$,$R = 2\ cal/mol\cdot K$,$\ln 2 = 0.7$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion : Wet air is heavier than dry air.
Reason : The density of dry air is more than density of water.