Assertion $(A)$: Fluorine has a smaller negative electron gain enthalpy than chlorine.
Reason $(R)$: The electron-electron repulsion is higher in chlorine than in fluorine.
Reason $(R)$: The electron-electron repulsion is higher in chlorine than in fluorine.
- ABoth $A$ and $R$ are correct and $R$ is the correct explanation of $A$.
- BBoth $A$ and $R$ are correct but $R$ is not the correct explanation of $A$.
- C$A$ is correct but $R$ is incorrect.
- D$A$ is incorrect but $R$ is correct.
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Similar Questions
Knowing the electron gain enthalpy values for $O \rightarrow O^{-}$ and $O \rightarrow O^{2-}$ as $-141 \ kJ \ mol^{-1}$ and $702 \ kJ \ mol^{-1}$ respectively,how can you account for the formation of a large number of oxides having $O^{2-}$ species and not $O^{-}$?
(Hint: Consider lattice energy factor in the formation of compounds).
(Hint: Consider lattice energy factor in the formation of compounds).
Medium
View Solution$A = 1s^2\, 2s^2\, 2p^4$,$B = 1s^2\, 2s^2\, 2p^5$,$C = 1s^2\, 2s^2\, 2p^6$. $A, B$ and $C$ are atoms/anions of the same element. Which one is correct? (One of $A/B/C$ is a neutral atom)
Difficult
View SolutionIdentify the set of elements in which they are arranged in the increasing order of electron gain enthalpies.
The correct order of electron gain enthalpy of $N$,$O$,$Cl$,$Al$ is
Select the equations that represent an endothermic step.
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