Assertion (A): When the plane of the coil is | vedclass

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(D) The magnetic flux $\phi$ linked with a coil is given by $\phi = \vec{B} \cdot \vec{A} = BA \cos 	heta$,where $	heta$ is the angle between the ma

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$(A)$ is false,$(R)$ is true.

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(D) The magnetic flux $\phi$ linked with a coil is given by $\phi = \vec{B} \cdot \vec{A} = BA \cos 	heta$,where $	heta$ is the angle between the magnetic field vector $\vec{B}$ and the area vector $\vec{A}$.When the plane of the coil is perpendicular to the magnetic field,the area vector $\vec{A}$ is parallel to the magnetic field $\vec{B}$,meaning $	heta = 0^{\circ}$.At $	heta = 0^{\circ}$,$\cos 0^{\circ} = 1$,so the flux $\phi = BA$ is maximum,not minimum.Since the assertion states that the flux is minimum when the plane is perpendicular,the assertion $(A)$ is false.The reason $(R)$ provides the correct formulas for flux and induced emf,so $(R)$ is true.Therefore,$(A)$ is false and $(R)$ is true.

Assertion $(A)$: When the plane of the coil is perpendicular to the magnetic field,the magnetic flux linked with the coil is minimum,but the induced emf is zero.
Reason $(R)$: $\phi = nAB \cos \theta$ and $e = -\frac{d\phi}{dt}$.

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Assertion $(A)$: When the plane of the coil is perpendicular to the magnetic field,the magnetic flux linked with the coil is minimum,but the induced emf is zero.Reason $(R)$: $\phi = nAB \cos \theta$ and $e = -\frac{d\phi}{dt}$.