Assertion (A): Na^{+} and Mg^{2+} ions are is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $Na^{+}$ and $Mg^{2+}$ are isoelectronic species having $10 \ e^{-}$ each.However,$Mg^{2+}$ has $12$ protons while $Na^{+}$ has $11$ protons.Due t

Vedclass · Accepted Answer

Both $(A)$ and $(R)$ are correct and $(R)$ is correct explanation of $(A)$.

Vedclass · Answer

(B) $Na^{+}$ and $Mg^{2+}$ are isoelectronic species having $10 \ e^{-}$ each.However,$Mg^{2+}$ has $12$ protons while $Na^{+}$ has $11$ protons.Due to a higher number of protons in $Mg^{2+}$,the effective nuclear charge $(Z_{eff})$ is greater for $Mg^{2+}$ than for $Na^{+}$.Since ionic radius is inversely proportional to the effective nuclear charge,the ionic radius of $Na^{+}$ is greater than that of $Mg^{2+}$.Therefore,both $(A)$ and $(R)$ are correct,and $(R)$ is the correct explanation of $(A)$.

Assertion $(A)$: $Na^{+}$ and $Mg^{2+}$ ions are isoelectronic but the ionic radius of $Na^{+}$ is greater than that of $Mg^{2+}$.
Reason $(R)$: The effective nuclear charge of $Na^{+}$ ion is less than that of $Mg^{2+}$ ion.

Similar Questions

The ions $S^{2-}, Cl^{-}, K^{+}, Ca^{2+}$ are isoelectronic. Their ionic radii show

The increasing order of the atomic radius of $Si, S, Na, Mg, Al$ is

Among the elements $Li$,$N$,$C$ and $Be$,the one with the largest atomic radius is

Which of the following has the largest ionic radius?

Which of the following represents the incorrect order of ionic size?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion $(A)$: $Na^{+}$ and $Mg^{2+}$ ions are isoelectronic but the ionic radius of $Na^{+}$ is greater than that of $Mg^{2+}$.Reason $(R)$: The effective nuclear charge of $Na^{+}$ ion is less than that of $Mg^{2+}$ ion.