Assertion: H_2O and XeF_4 both have a plane o | vedclass

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Question

(A) $H_2O$ has a bent structure ($sp^3$ hybridization) and possesses a plane of symmetry (the molecular plane). It is a polar molecule due to the net

Vedclass · Accepted Answer

Both Assertion and Reason are true,but Reason is $NOT$ the correct explanation of Assertion.

Vedclass · Answer

(A) $H_2O$ has a bent structure ($sp^3$ hybridization) and possesses a plane of symmetry (the molecular plane). It is a polar molecule due to the net dipole moment. $XeF_4$ has a square planar structure ($sp^3d^2$ hybridization) and possesses multiple planes of symmetry (including the molecular plane). It is non-polar because the individual bond dipoles cancel each other out. Both statements are true,but the polarity of the molecules is not the reason for the existence of a plane of symmetry. Therefore,the Reason is not the correct explanation of the Assertion.

Assertion: $H_2O$ and $XeF_4$ both have a plane of symmetry.
Reason: $H_2O$ is a polar molecule,whereas $XeF_4$ is a non-polar molecule.

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Assertion: $H_2O$ and $XeF_4$ both have a plane of symmetry. Reason: $H_2O$ is a polar molecule,whereas $XeF_4$ is a non-polar molecule.