Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$Fe(OH)_3 \downarrow + NaOH(\text{excess}) \longrightarrow \text{No reaction}$
$Fe(OH)_3 \downarrow + NaOH(\text{excess}) \longrightarrow \text{No reaction}$
- AFor precipitate formation reaction
- BFor precipitate dissolution reaction
- CFor precipitate exchange reaction
- DFor no reaction
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Which of the following solutions will yield a black precipitate when $H_2S$ gas is passed through it?
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View SolutionWhich sulphide is soluble in $(NH_4)_2CO_3$?
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View SolutionConsider the following reactions:
$X(aq.) \xrightarrow{K_4[Fe(CN)_6]}$ Chocolate brown ppt.
$X(aq.) \xrightarrow{AgNO_3}$ White ppt. (insoluble in dil. $HNO_3$)
Then $X$ will be:
$X(aq.) \xrightarrow{K_4[Fe(CN)_6]}$ Chocolate brown ppt.
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View SolutionMatch the List-$I$ with List-$II$ :
Cations Group reaction $P \rightarrow Pb^{2+}, Cu^{2+}$ $(i)$ $H_2S$ gas in presence of dilute $HCl$ $Q \rightarrow Al^{3+}, Fe^{3+}$ $(ii)$ $(NH_4)_2CO_3$ in presence of $NH_4OH$ $R \rightarrow Co^{2+}, Ni^{2+}$ $(iii)$ $NH_4OH$ in presence of $NH_4Cl$ $S \rightarrow Ba^{2+}, Ca^{2+}$ $(iv)$ $H_2S$ in presence of $NH_4OH$
| Cations | Group reaction |
| $P \rightarrow Pb^{2+}, Cu^{2+}$ | $(i)$ $H_2S$ gas in presence of dilute $HCl$ |
| $Q \rightarrow Al^{3+}, Fe^{3+}$ | $(ii)$ $(NH_4)_2CO_3$ in presence of $NH_4OH$ |
| $R \rightarrow Co^{2+}, Ni^{2+}$ | $(iii)$ $NH_4OH$ in presence of $NH_4Cl$ |
| $S \rightarrow Ba^{2+}, Ca^{2+}$ | $(iv)$ $H_2S$ in presence of $NH_4OH$ |
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