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Question

(C) In the reaction $CuO + H_2 \longrightarrow Cu + H_2O$:$1$. The oxidation state of $Cu$ changes from $+2$ in $CuO$ to $0$ in $Cu$ (reduction).$2$.

Vedclass · Accepted Answer

for either intermolecular redox reaction or displacement reaction.

Vedclass · Answer

(C) In the reaction $CuO + H_2 \longrightarrow Cu + H_2O$:$1$. The oxidation state of $Cu$ changes from $+2$ in $CuO$ to $0$ in $Cu$ (reduction).$2$. The oxidation state of $H$ changes from $0$ in $H_2$ to $+1$ in $H_2O$ (oxidation).$3$. Since one element is oxidized and another is reduced,it is an intermolecular redox reaction.$4$. Additionally,$H_2$ displaces $Cu$ from $CuO$,making it a displacement reaction.$5$. Therefore,the reaction is classified as either an intermolecular redox reaction or a displacement reaction.

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$CuO + H_2 \longrightarrow Cu + H_2O$

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Assign $A$,$B$,$C$,$D$ from the given type of reaction.$CuO + H_2 \longrightarrow Cu + H_2O$