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(C) The reaction is: $2NaNO_2 + 3FeSO_4 + 3H_2SO_4 \longrightarrow Fe_2(SO_4)_3 + Na_2SO_4 + 2H_2O + 2NO$Then,$FeSO_4 + NO + 5H_2O \longrightarrow [Fe

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$C$. Intermolecular redox reaction.

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(C) The reaction is: $2NaNO_2 + 3FeSO_4 + 3H_2SO_4 \longrightarrow Fe_2(SO_4)_3 + Na_2SO_4 + 2H_2O + 2NO$Then,$FeSO_4 + NO + 5H_2O \longrightarrow [Fe(H_2O)_5NO]SO_4$.In the first step,the oxidation state of $N$ changes from $+3$ (in $NaNO_2$) to $+2$ (in $NO$),and the oxidation state of $Fe$ changes from $+2$ (in $FeSO_4$) to $+3$ (in $Fe_2(SO_4)_3$).Since different elements are oxidized and reduced in the same reaction,it is an intermolecular redox reaction.

Assign $A, B, C, D$ from the given type of reaction.
$NaNO_2 + FeSO_4 + H_2SO_4 \longrightarrow [Fe(H_2O)_5NO]SO_4 + Na_2SO_4 + Fe_2(SO_4)_3 + H_2O$
Identify the type of reaction for the formation of the brown ring complex.

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Assign $A, B, C, D$ from the given type of reaction.$NaNO_2 + FeSO_4 + H_2SO_4 \longrightarrow [Fe(H_2O)_5NO]SO_4 + Na_2SO_4 + Fe_2(SO_4)_3 + H_2O$Identify the type of reaction for the formation of the brown ring complex.