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(C) In the reaction $Sn + PCl_5 \xrightarrow{\Delta} SnCl_4 + PCl_3$,the oxidation state of $Sn$ changes from $0$ to $+4$ (oxidation).The oxidation st

Vedclass · Accepted Answer

$C$. for either intermolecular redox reaction or displacement reaction.

Vedclass · Answer

(C) In the reaction $Sn + PCl_5 \xrightarrow{\Delta} SnCl_4 + PCl_3$,the oxidation state of $Sn$ changes from $0$ to $+4$ (oxidation).The oxidation state of $P$ changes from $+5$ to $+3$ (reduction).Since one reactant $(Sn)$ is oxidized and another reactant $(PCl_5)$ is reduced,this is an intermolecular redox reaction.Additionally,$Sn$ displaces $P$ from $PCl_5$,making it a displacement reaction.Therefore,the correct classification is $C$.

Assign $A, B, C, D$ from the given type of reaction.
$Sn + PCl_5 \xrightarrow{\Delta} SnCl_4 + PCl_3$

Similar Questions

$MnO_4^-$ on reduction in acidic medium forms

Balance the redox reaction where $Fe^{+2}$ in an acidic medium reduces $Cr_2O_7^{-2}$ ion to $Cr^{+3}$ ion,while $Fe^{+2}$ itself is oxidized to $Fe^{+3}$.

For the redox reaction $MnO_4^- + C_2O_4^{2-} + H^{+} \to Mn^{2+} + CO_2 + H_2O$,the correct coefficients of the reactants for the balanced reaction are:
$MnO_4^-$ : $C_2O_4^{2-}$ : $H^{+}$

Number of moles of $SnCl_2$ required for the reduction of $1$ mole of $K_2Cr_2O_7$ into $Cr^{3+}$ (in acidic medium) is:

$A$ solution of $Na_2S_2O_3$ is standardized iodometrically against $0.167 \ g$ of $KBrO_3$ where $BrO_3^-$ changes to $Br^-$. This process requires $45 \ mL$ of the $Na_2S_2O_3$ solution. What is the strength of the $Na_2S_2O_3$ in $N$?
$[Mw \text{ of } KBrO_3 = 167]$

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Assign $A, B, C, D$ from the given type of reaction.$Sn + PCl_5 \xrightarrow{\Delta} SnCl_4 + PCl_3$