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(D) In the given reaction: $2NaNO_3 + H_2SO_4 \xrightarrow{Hot} Na_2SO_4 + 2NO_2 + \frac{1}{2}O_2 + H_2O$. $1$. The oxidation state of $N$ in $NaNO_3$

Vedclass · Accepted Answer

$D$. for either thermal combination redox reaction or thermal decomposition redox reaction.

Vedclass · Answer

(D) In the given reaction: $2NaNO_3 + H_2SO_4 \xrightarrow{Hot} Na_2SO_4 + 2NO_2 + \frac{1}{2}O_2 + H_2O$. $1$. The oxidation state of $N$ in $NaNO_3$ is $+5$. $2$. The oxidation state of $N$ in $NO_2$ is $+4$. $3$. The oxidation state of $O$ in $NaNO_3$ is $-2$,and in $O_2$ it is $0$. $4$. Since $NaNO_3$ undergoes thermal decomposition to form $NO_2$ and $O_2$ with a change in oxidation states,it is a thermal decomposition redox reaction. $5$. Therefore,the correct classification is $D$.

Assign $A, B, C, D$ from the given type of reaction: $2NaNO_3 + H_2SO_4(conc.) \xrightarrow{Hot} Na_2SO_4 + 2NO_2 + \frac{1}{2}O_2 + H_2O$. (Note: The reaction is a thermal decomposition redox reaction).

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