Assume that $P(A) = P(B)$. Show that $A = B$.

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Given that $P(A) = P(B)$.
To show: $A = B$.
Let $x \in A$.
Since $A \in P(A)$ and $P(A) = P(B)$,it follows that $A \in P(B)$.
By the definition of the power set,if $A \in P(B)$,then $A \subseteq B$.
Therefore,$x \in A \implies x \in B$,which means $A \subseteq B$.
Similarly,let $y \in B$. Since $B \in P(B)$ and $P(B) = P(A)$,it follows that $B \in P(A)$.
By the definition of the power set,if $B \in P(A)$,then $B \subseteq A$.
Therefore,$y \in B \implies y \in A$,which means $B \subseteq A$.
Since $A \subseteq B$ and $B \subseteq A$,we conclude that $A = B$.

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