(D) For a solution,$pH = -\log[H^{+}]$.Given $pH = 1$,so $[H^{+}] = 10^{-1} = 0.1\,M$.For $H_2SO_4$,the dissociation is $H_2SO_4 \rightarrow 2H^{+} +

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(D) For a solution,$pH = -\log[H^{+}]$.Given $pH = 1$,so $[H^{+}] = 10^{-1} = 0.1\,M$.For $H_2SO_4$,the dissociation is $H_2SO_4 \rightarrow 2H^{+} + SO_4^{2-}$.Since $1\,mol$ of $H_2SO_4$ produces $2\,mol$ of $H^{+}$,the concentration of $H^{+}$ is $2 \times [H_2SO_4]$.Therefore,$0.1 = 2 \times [H_2SO_4]$.$[H_2SO_4] = \frac{0.1}{2} = 0.05\,M$.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)pH of strong Acids and strong Bases

Easy

Assuming complete ionisation,the $pH$ of $0.1\,M\,HCl$ is $1$. The molarity of $H_2SO_4$ with the same $pH$ is (in $,M$)

A
$0.2$
B
$0.1$
C
$2$
D
$0.05$

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6-2.Equilibrium-II (Ionic Equilibrium)

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pH of strong Acids and strong Bases

Which of the following will decrease the $pH$ of a $50 \ mL$ solution of $0.01 \ M \ HCl$?

DifficultWBJEE 2009

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What will be the resultant $pH$ when $100 \ mL$ of an aqueous solution of $HCl$ $(pH = 2)$ is mixed with $200 \ mL$ of an aqueous solution of $NaOH$ $(pH = 12)$?

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$pH$ value of $0.001 \ M \ NaOH$ solution is $..... .$

EasyJEE MAIN 2022

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When a base is dissolved in water,it produces a hydroxide ion concentration of $0.05 \ mol/L$. Therefore,this solution will be.......

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Assuming complete ionisation,the $pH$ of $0.1\,M\,HCl$ is $1$. The molarity of $H_2SO_4$ with the same $pH$ is (in $,M$)

Similar Questions

Which of the following will decrease the $pH$ of a $50 \ mL$ solution of $0.01 \ M \ HCl$?

Given that the dissociation constant for $H_2O$ is $K_w = 1 \times 10^{-14} \ mol^2 \ L^{-2}$,what is the $pH$ of a $0.001 \ M \ KOH$ solution?

What will be the resultant $pH$ when $100 \ mL$ of an aqueous solution of $HCl$ $(pH = 2)$ is mixed with $200 \ mL$ of an aqueous solution of $NaOH$ $(pH = 12)$?

$pH$ value of $0.001 \ M \ NaOH$ solution is $..... .$

When a base is dissolved in water,it produces a hydroxide ion concentration of $0.05 \ mol/L$. Therefore,this solution will be.......

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