Assuming that the degree of hydrolysis is sma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Sodium acetate is a salt of a strong base $(NaOH)$ and a weak acid $(CH_3COOH)$.The formula for the $pH$ of a salt of a strong base and a weak aci

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(D) Sodium acetate is a salt of a strong base $(NaOH)$ and a weak acid $(CH_3COOH)$.The formula for the $pH$ of a salt of a strong base and a weak acid is given by:$pH = 7 + \frac{1}{2}pK_a + \frac{1}{2} \log c$Given:$c = 0.1 \ M = 10^{-1} \ M$$K_a = 1.0 	imes 10^{-5}$Step $1$: Calculate $pK_a$$pK_a = - \log K_a = - \log (10^{-5}) = 5$Step $2$: Calculate $\log c$$\log c = \log (10^{-1}) = -1$Step $3$: Calculate $pH$$pH = 7 + \frac{1}{2}(5) + \frac{1}{2}(-1)$$pH = 7 + 2.5 - 0.5$$pH = 9.0$

Assuming that the degree of hydrolysis is small,the $pH$ of $0.1 \ M$ solution of sodium acetate $(K_a = 1.0 \times 10^{-5})$ will be

Similar Questions

The degree of hydrolysis of a $0.1 \ M$ solution of $ArNH_3^+ Cl^-$ is $0.01$. Find the degree of hydrolysis in a $0.4 \ M$ solution of $ArNH_3^+ Cl^-$.

Identify from the following salts an example of a salt of a strong acid and a weak base.

Find the equilibrium constant for the equilibrium reaction:
$HCOO^{-} + H_2O \rightleftharpoons HCOOH + OH^{-}$
Given that the dissociation constant of formic acid is $K_a(HCOOH) = 1.8 \times 10^{-4}$.

The approximate $pH$ of $0.01 \ M \ NaHA$ is calculated by: ($K_{a_1} = 10^{-6}$ and $K_{a_2} = 10^{-8}$ are ionization constants of $H_2A$)

Which of the following aqueous solutions will have the highest $pH$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module