Assuming that the dimmest visible star to the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The relationship between the brightness ratio of two celestial objects and their magnitudes is given by the formula: $\frac{I_1}{I_2} = 100^{(m_2

Vedclass · Accepted Answer

$10000$

Vedclass · Answer

(A) The relationship between the brightness ratio of two celestial objects and their magnitudes is given by the formula: $\frac{I_1}{I_2} = 100^{(m_2 - m_1)/5}$.Here,for Venus,the magnitude $m_1 = -4$.For the dimmest visible star,the magnitude $m_2 = 6$.Substituting these values into the formula:$\frac{I_1}{I_2} = 100^{(6 - (-4))/5} = 100^{10/5} = 100^2$.Calculating the result: $100^2 = 10,000$.Therefore,Venus is $10,000$ times brighter than the dimmest visible star.

Assuming that the dimmest visible star to the naked eye has a magnitude of about $6$. The brightness of planet Venus (magnitude = $-4$) with respect to this star is ........ times brighter.

Similar Questions

If a galaxy is at a distance of $430$ million light years from us,what is the Hubble's constant in $km s^{-1}$ per million light years? Its speed is $6.48 \times 10^6 m s^{-1}$.

There are certain types of stars called variable stars which undergo periodic changes in their light output. If such a star quadruples its light output,how much does its magnitude change?

Which of the following represents the correct order of the evolution of the universe?

The length of the Milky Way is .......... light years.

According to the pulsating theory,the expansion and contraction of the universe repeats after every

Vedclass Test Series

Exam Paper Generator

Online Exam Module