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(B) In the given circuit, the two diodes are connected in parallel in opposite directions. One diode is forward-biased, while the other is reverse-bia

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(B) In the given circuit, the two diodes are connected in parallel in opposite directions. One diode is forward-biased, while the other is reverse-biased. The forward-biased diode acts as a short circuit (since its forward resistance is zero), and the reverse-biased diode acts as an open circuit. Thus, the total resistance in the circuit is $R = 2 \, k\Omega = 2000 \, \Omega$. The voltage source is $E = 20 \, V$. Using Ohm's law, the current $I$ is given by: $I = \frac{E}{R} = \frac{20 \, V}{2000 \, \Omega} = 0.01 \, A = 10 \, mA$.

Assuming the diodes to be of silicon with forward resistance zero, the current $I$ in the following circuit is.......$mA$

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