At $298 \, K$,the equivalent conductivity of a $0.01 \, M$ solution of aniline hydrochloride is $122.5 \, \Omega^{-1} \, cm^2 \, eq^{-1}$,but in the presence of a sufficient excess of aniline to prevent hydrolysis,it is $106.5 \, \Omega^{-1} \, cm^2 \, eq^{-1}$. The equivalent conductivity of $HCl$ at infinite dilution is $426.0 \, \Omega^{-1} \, cm^2 \, eq^{-1}$. The hydrolysis constant of aniline is:

  • A
    $0.05$
  • B
    $2.63 \times 10^{-5}$
  • C
    $4.86 \times 10^{-5}$
  • D
    $2.18 \times 10^{-8}$

Explore More

Similar Questions

When the $pH$ of a solution is $2$,the hydrogen ion concentration in moles per litre is

The $pH$ of a neutral solution in our body at normal temperature is ..........

Calculate $[H^{+}]$ concentration for solutions with $pH = 12.0$ and $pH = 5.6$.

Identify the incorrect statement.

Which equation represents the calculation of the ionic product for distilled water?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo