At 25^{circ} C and 760 ,mm ,Hg pressure,a gas | vedclass

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Question

(A) Given:$p_{1} = 760 \,mm \,Hg$,$V_{1} = 600 \,mL$,$T_{1} = 25 + 273 = 298 \,K$$V_{2} = 640 \,mL$,$T_{2} = 10 + 273 = 283 \,K$Using the combined gas

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$676.6 \,mm \,Hg$

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(A) Given:$p_{1} = 760 \,mm \,Hg$,$V_{1} = 600 \,mL$,$T_{1} = 25 + 273 = 298 \,K$$V_{2} = 640 \,mL$,$T_{2} = 10 + 273 = 283 \,K$Using the combined gas law:$\frac{p_{1} V_{1}}{T_{1}} = \frac{p_{2} V_{2}}{T_{2}}$Rearranging for $p_{2}$:$p_{2} = \frac{p_{1} V_{1} T_{2}}{T_{1} V_{2}}$Substituting the values:$p_{2} = \frac{760 	imes 600 	imes 283}{298 	imes 640}$$p_{2} = \frac{129048000}{190720} \approx 676.6 \,mm \,Hg$

At $25^{\circ} C$ and $760 \,mm \,Hg$ pressure,a gas occupies $600 \,mL$ volume. What will be its pressure at a height where the temperature is $10^{\circ} C$ and the volume of the gas is $640 \,mL$?

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