At T K,consider the following gaseous reactio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the initial pressure of $N_2O_5$ be $P_0 = 300 \ mm \ Hg$. Let $\alpha$ be the fraction of $N_2O_5$ decomposed. The reaction is: $N_2O_5 \righ

Vedclass · Accepted Answer

$0.4$

Vedclass · Answer

(C) Let the initial pressure of $N_2O_5$ be $P_0 = 300 \ mm \ Hg$. Let $\alpha$ be the fraction of $N_2O_5$ decomposed. The reaction is: $N_2O_5 \rightleftharpoons 2NO_2 + \frac{1}{2}O_2$. At $t=0$: $P_0, 0, 0$. At equilibrium: $P_0(1-\alpha), 2P_0\alpha, \frac{1}{2}P_0\alpha$. Total pressure at equilibrium $P_t = P_0(1-\alpha) + 2P_0\alpha + 0.5P_0\alpha = P_0(1 + 1.5\alpha)$. Given $P_t = 480 \ mm \ Hg$ and $P_0 = 300 \ mm \ Hg$. $480 = 300(1 + 1.5\alpha)$. $1.6 = 1 + 1.5\alpha$. $0.6 = 1.5\alpha$. $\alpha = \frac{0.6}{1.5} = 0.4$.

Similar Questions

If the density of air at $STP$ is $0.001293 \, g \, mL^{-1}$,what will be its vapor density?

At $STP$,the density of air is $0.001293 \ g \ mL^{-1}$. Its vapour density is $---$.

For the equations $(i) \ HCN + CCl_4 \rightarrow \alpha_1$ and $(ii) \ HCN + C_6H_6 \rightarrow \alpha_2$,which degree of dissociation is greater,$\alpha_1$ or $\alpha_2$?

The degree of dissociation $(\alpha)$ of $PCl_5$ obeying the equilibrium $PCl_5 \rightleftharpoons PCl_3 + Cl_2$ is related to the pressure at equilibrium by

Given is a concentrated solution of a weak electrolyte $A_{x}B_{y}$ of concentration '$c$' and dissociation constant '$K$'. The degree of dissociation is given by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module