(B) One mole of gas at $STP$ occupies $22.4 \ L$.Thus,$5.6 \ L$ of gas at $STP$ contains $n = \frac{5.6}{22.4} = 0.25 \ \text{moles}$.Number of moles

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(B) One mole of gas at $STP$ occupies $22.4 \ L$.Thus,$5.6 \ L$ of gas at $STP$ contains $n = \frac{5.6}{22.4} = 0.25 \ \text{moles}$.Number of moles = $\frac{\text{weight in gram}}{\text{molecular weight (M)}}$.$0.25 = \frac{7.5}{M}$.$M = \frac{7.5}{0.25} = 30 \ \text{g/mol}$.The molar mass of $NO$ is $14 + 16 = 30 \ \text{g/mol}$.Thus,the gas is $NO$.Hence,the correct option is $B$.

Class 11 Chemistry Some Basic Concepts of Chemistry Atomic, Molecular and Equivalent masses

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At $STP$,if $5.6 \ L$ of a gas weighs $7.5 \ g$,then identify the gas.

AP EAMCET 2020 All AP EAMCET

A
$CO$
B
$NO$
C
$NO_2$
D
$CO_2$

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Some Basic Concepts of Chemistry

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Atomic, Molecular and Equivalent masses

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At $STP$,if $5.6 \ L$ of a gas weighs $7.5 \ g$,then identify the gas.

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