At STP,'x' g of a metal hydrogen carbonate (M | vedclass

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(B) The reaction between $CO_2$ and $MOH$ is: $CO_2 + MOH \rightarrow MHCO_3$. Since $0.2 \ mol$ of $MOH$ reacts completely,$0.2 \ mol$ of $CO_2$ is p

Vedclass · Accepted Answer

$33.6$

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(B) The reaction between $CO_2$ and $MOH$ is: $CO_2 + MOH ightarrow MHCO_3$. Since $0.2 \ mol$ of $MOH$ reacts completely,$0.2 \ mol$ of $CO_2$ is produced. The thermal decomposition of metal hydrogen carbonate is: $2MHCO_3 \xrightarrow{\Delta} M_2CO_3 + CO_2 + H_2O$. From the stoichiometry,$1 \ mol$ of $CO_2$ is produced from $2 \ mol$ of $MHCO_3$. Therefore,$0.2 \ mol$ of $CO_2$ is produced from $2 	imes 0.2 = 0.4 \ mol$ of $MHCO_3$. The mass '$x$' is calculated as: $x = 	ext{moles} 	imes 	ext{molar mass} = 0.4 \ mol 	imes 84 \ g \ mol^{-1} = 33.6 \ g$.

At $STP$,'$x$' $g$ of a metal hydrogen carbonate $(MHCO_3)$ (molar mass $84 \ g \ mol^{-1}$) on heating gives $CO_2$,which can completely react with $0.2 \ mol$ of $MOH$ (molar mass $40 \ g \ mol^{-1}$) to give $MHCO_3$. The value of '$x$' is

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