At a given place where acceleration due to gr | vedclass

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(C) The forces acting on the sphere are its weight $(W = Vdg)$ acting downwards and the buoyant force $(F_B = V\rho g)$ acting upwards,where $V$ is th

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Fall vertically with an acceleration $g \left( \frac{d - \rho}{d} \right)$

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(C) The forces acting on the sphere are its weight $(W = Vdg)$ acting downwards and the buoyant force $(F_B = V\rho g)$ acting upwards,where $V$ is the volume of the sphere.According to Newton's second law,the net force $F_{net} = ma = Vda$.$Vda = Vdg - V\rho g$Dividing both sides by $Vd$,we get:$a = g - \frac{\rho g}{d} = g \left( 1 - \frac{\rho}{d} \right) = g \left( \frac{d - \rho}{d} \right)$.Thus,the sphere falls vertically with an acceleration of $g \left( \frac{d - \rho}{d} \right)$.

At a given place where acceleration due to gravity is $g \ m/s^2$,a sphere of lead of density $d \ kg/m^3$ is gently released in a column of liquid of density $\rho \ kg/m^3$. If $d > \rho$,the sphere will:

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