At a village trade fair,a man buys a horse an | vedclass

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(D) Let the cost price of the horse be $x$ and the cost price of the camel be $(51250 - x)$.According to the problem,the selling price of both animals

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$20000$

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(D) Let the cost price of the horse be $x$ and the cost price of the camel be $(51250 - x)$.According to the problem,the selling price of both animals is the same.Selling price of horse = $x + 25\% 	ext{ of } x = 1.25x$.Selling price of camel = $(51250 - x) - 20\% 	ext{ of } (51250 - x) = 0.8(51250 - x)$.Equating the two selling prices:$1.25x = 0.8(51250 - x)$$1.25x = 41000 - 0.8x$$1.25x + 0.8x = 41000$$2.05x = 41000$$x = \frac{41000}{2.05} = 20000$.Cost price of the horse = $Rs. 20,000$.Cost price of the camel = $51250 - 20000 = Rs. 31,250$.The cheaper animal is the horse,with a cost price of $Rs. 20,000$.

At a village trade fair,a man buys a horse and a camel together for $Rs. 51,250$. He sold the horse at a profit of $25\%$ and the camel at a loss of $20\%$. If he sold both the animals at the same price,then the cost price of the cheaper animal was $Rs.$ .........

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