At high pressure,the form of Van der Waals eq | vedclass

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(B) The Van der Waals equation for $1$ mole of gas is $\left( P + \frac{a}{V^2} \right) (V - b) = RT$.At high pressure,the volume $V$ is small,so the

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$P(V - b) = RT$

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(B) The Van der Waals equation for $1$ mole of gas is $\left( P + \frac{a}{V^2} \right) (V - b) = RT$.At high pressure,the volume $V$ is small,so the correction term $\frac{a}{V^2}$ becomes very large compared to $P$. However,the term $(V - b)$ cannot be neglected because $V$ is comparable to $b$.Thus,the pressure correction term $\frac{a}{V^2}$ is neglected relative to $P$,simplifying the equation to $P(V - b) = RT$.

At high pressure,the form of Van der Waals equation becomes

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