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(A) The frequency of vibration of a stretched wire is given by $n = \frac{1}{2l} \sqrt{\frac{T}{m}}$.Here,$T$ is the tension in the wire,which is prov

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should be decreased.

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(A) The frequency of vibration of a stretched wire is given by $n = \frac{1}{2l} \sqrt{\frac{T}{m}}$.Here,$T$ is the tension in the wire,which is provided by the weight of a mass $M$ suspended from it,so $T = Mg$.Thus,$n = \frac{1}{2l} \sqrt{\frac{Mg}{m}}$.For the frequency $n$ to remain constant with the same tuning fork,we have $\frac{1}{l} \sqrt{g} = 	ext{constant}$.This implies $l \propto \sqrt{g}$.Since the acceleration due to gravity $g$ is greater at the poles $(g_p)$ than at the equator $(g_e)$,i.e.,$g_p > g_e$,it follows that the length $l$ must be adjusted.To maintain the same frequency at the equator where $g$ is smaller,the length $l$ must be decreased to compensate for the decrease in $g$ such that the ratio $\frac{\sqrt{g}}{l}$ remains constant.Therefore,the vibrating length of the wire should be decreased.

At the poles of the earth,a stretched wire of a given length vibrates in unison with a tuning fork. At the equator of the earth,for the same setting,to produce resonance with the same fork,the vibrating length of the wire

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