The axis of the parabola x^2 - 4x - 3y + 10 = | vedclass

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(D) Given the equation of the parabola is $x^2 - 4x - 3y + 10 = 0$. Rearranging the terms,we get $x^2 - 4x = 3y - 10$. Completing the square on the le

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$x - 2 = 0$

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(D) Given the equation of the parabola is $x^2 - 4x - 3y + 10 = 0$. Rearranging the terms,we get $x^2 - 4x = 3y - 10$. Completing the square on the left side: $x^2 - 4x + 4 = 3y - 10 + 4$. This simplifies to $(x - 2)^2 = 3y - 6$. $(x - 2)^2 = 3(y - 2)$. Comparing this with the standard form $(x - h)^2 = 4a(y - k)$,the axis of the parabola is $x - h = 0$. Therefore,the axis is $x - 2 = 0$.

The axis of the parabola $x^2 - 4x - 3y + 10 = 0$ is

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