Balance the following redox reactions using the oxidation number and ion-electron method:
$(1) \ Zn + NO_3^- + H^+ \to Zn^{2+} + N_2O + H_2O$
$(2) \ I^- + O_2 + H_2O \to I_2 + OH^-$
$(3) \ MnO_4^- + C_2H_5OH \to Mn^{2+} + CH_3COOH$
$(1) \ Zn + NO_3^- + H^+ \to Zn^{2+} + N_2O + H_2O$
$(2) \ I^- + O_2 + H_2O \to I_2 + OH^-$
$(3) \ MnO_4^- + C_2H_5OH \to Mn^{2+} + CH_3COOH$
(N/A) $(1) \ 4Zn + 2NO_3^- + 10H^+ \to 4Zn^{2+} + N_2O + 5H_2O$
$(2) \ 4I^- + O_2 + 2H_2O \to 2I_2 + 4OH^-$
$(3) \ 4MnO_4^- + 5C_2H_5OH + 12H^+ \to 4Mn^{2+} + 5CH_3COOH + 11H_2O$
$(2) \ 4I^- + O_2 + 2H_2O \to 2I_2 + 4OH^-$
$(3) \ 4MnO_4^- + 5C_2H_5OH + 12H^+ \to 4Mn^{2+} + 5CH_3COOH + 11H_2O$
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Similar Questions
Which of the following is not correct?
Match the following columns:-
Column-$I$ [Type of reaction] Column-$II$ [Example] $I$. Intermolecular redox reaction $A$. $CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O$ $II$. Intramolecular redox reaction $B$. $NH_4NO_2 \rightarrow N_2 + 2H_2O$ $III$. Disproportionation reaction $C$. $2H_2O_2 \rightarrow 2H_2O + O_2$ $IV$. Comproportionation reaction $D$. $KClO_3 \rightarrow KCl + \frac{3}{2}O_2$
| Column-$I$ [Type of reaction] | Column-$II$ [Example] |
|---|---|
| $I$. Intermolecular redox reaction | $A$. $CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O$ |
| $II$. Intramolecular redox reaction | $B$. $NH_4NO_2 \rightarrow N_2 + 2H_2O$ |
| $III$. Disproportionation reaction | $C$. $2H_2O_2 \rightarrow 2H_2O + O_2$ |
| $IV$. Comproportionation reaction | $D$. $KClO_3 \rightarrow KCl + \frac{3}{2}O_2$ |
Medium
View SolutionAssign $A$,$B$,$C$,$D$ from the given type of reaction.
$Ca(OH)_2 + CO_2 \longrightarrow CaCO_3 \downarrow + H_2O$
$Ca(OH)_2 + CO_2 \longrightarrow CaCO_3 \downarrow + H_2O$
Medium
View SolutionAcidified $KMnO_4$ can be decolourised by
Easy
View SolutionAqueous sulphite reacts with dilute sulphuric acid to form $X_{(g)}$. The liberated $X_{(g)}$ is passed into acidified $KMnO_4$ solution. What is the oxidation state of $Mn$ in the product formed?
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