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(C) According to Heisenberg's uncertainty principle:$m \Delta V \cdot \Delta x \geq \frac{h}{4 \pi}$Given:$\Delta x = 10^{-15} \ m$$m = 9.1 	imes 10^

Vedclass · Accepted Answer

$58$

Vedclass · Answer

(C) According to Heisenberg's uncertainty principle:$m \Delta V \cdot \Delta x \geq \frac{h}{4 \pi}$Given:$\Delta x = 10^{-15} \ m$$m = 9.1 	imes 10^{-31} \ kg$$h = 6.626 	imes 10^{-34} \ Js$$\pi = 3.14$Substituting the values:$\Delta V = \frac{h}{4 \pi m \Delta x}$$\Delta V = \frac{6.626 	imes 10^{-34}}{4 	imes 3.14 	imes 9.1 	imes 10^{-31} 	imes 10^{-15}}$$\Delta V = \frac{6.626 	imes 10^{-34}}{114.296 	imes 10^{-46}}$$\Delta V = 0.05797 	imes 10^{12} \ ms^{-1}$$\Delta V = 57.97 	imes 10^9 \ ms^{-1}$Rounding to the nearest integer,we get $58 	imes 10^9 \ ms^{-1}$.

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