Benzene + CH_3CH_2CH_2Cl xrightarrow{AlCl_3} | vedclass

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(A) $1$. The reaction of benzene with $n$-propyl chloride in the presence of $AlCl_3$ is a Friedel-Crafts alkylation. Due to the rearrangement of the

Vedclass · Accepted Answer

Isopropylbenzene and $CH_3COCH_3$

Vedclass · Answer

(A) $1$. The reaction of benzene with $n$-propyl chloride in the presence of $AlCl_3$ is a Friedel-Crafts alkylation. Due to the rearrangement of the primary carbocation to a more stable secondary carbocation,the major product $M$ is isopropylbenzene (cumene).$2$. Cumene $(M)$ reacts with $O_2$ at high temperature to form cumene hydroperoxide.$3$. Upon treatment with $H_3O^+$,cumene hydroperoxide undergoes acid-catalyzed rearrangement to yield phenol and acetone $(CH_3COCH_3)$.$4$. Thus,$M$ is isopropylbenzene and $N$ is acetone $(CH_3COCH_3)$.

List-$I$ (Compound)	List-$II$ ($pK_a$ value)
$A$. Ethanol	$I$. $10.0$
$B$. Phenol	$II$. $15.9$
$C$. $m$-Nitrophenol	$III$. $7.1$
$D$. $p$-Nitrophenol	$IV$. $8.3$

Benzene $+ CH_3CH_2CH_2Cl$ $\xrightarrow{AlCl_3} M$ $\xrightarrow{(i) O_2/\Delta , (ii) H_3O^+} N + \text{phenol}$. Here $M$ and $N$ are

Similar Questions

Arrange the following compounds in increasing order of their acid strength: $Propan-1-ol$,$2,4,6-trinitrophenol$,$3-nitrophenol$,$3,5-dinitrophenol$,$phenol$,$4-methylphenol$.

Match List-$I$ with List-$II$:

List-$I$ (Compound) List-$II$ ($pK_a$ value)

$A$. Ethanol $I$. $10.0$

$B$. Phenol $II$. $15.9$

$C$. $m$-Nitrophenol $III$. $7.1$

$D$. $p$-Nitrophenol $IV$. $8.3$

Choose the correct answer from the options given below:

Identify $X$ and $Y$ in the following reactions:

Which of the following produces violet colour with $FeCl_3$ solution?

The $pK_{a}$ values of $X, Y, Z$ respectively are $8.3, 7.1, 10.2$. What are $X, Y, Z$?

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