Benzyl isocyanide can be obtained from which | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. Reaction $A$: Benzyl bromide $(C_6H_5CH_2Br)$ reacts with $AgCN$ to form benzyl isocyanide $(C_6H_5CH_2NC)$. This is because $AgCN$ is a cova

Vedclass · Accepted Answer

$A$ and $B$ Only

Vedclass · Answer

(A) $1$. Reaction $A$: Benzyl bromide $(C_6H_5CH_2Br)$ reacts with $AgCN$ to form benzyl isocyanide $(C_6H_5CH_2NC)$. This is because $AgCN$ is a covalent compound, and the nucleophilic attack occurs through the nitrogen atom of the ambident $CN^-$ ion.$2$. Reaction $B$: Benzylamine $(C_6H_5CH_2NH_2)$ undergoes the carbylamine reaction with $CHCl_3$ and $KOH$ (or $NaOH$) to form benzyl isocyanide $(C_6H_5CH_2NC)$.$3$. Reaction $C$: Bromobenzene does not undergo nucleophilic substitution with $AgCN$ under normal conditions due to the partial double bond character of the $C-Br$ bond.$4$. Reaction $D$: Aniline $(C_6H_5NH_2)$ undergoes the carbylamine reaction to form phenyl isocyanide $(C_6H_5NC)$, not benzyl isocyanide.$5$. Reaction $E$: $2-$Phenylethyl bromide reacts with $KCN$ to form $3-$phenylpropanenitrile $(C_6H_5CH_2CH_2CN)$.Therefore, benzyl isocyanide is obtained from reactions $A$ and $B$.

List-$I$	List-$II$
$I.$ Benzenesulphonyl Chloride	$A.$ Zwitterion
$II.$ Sulphanilic acid	$B.$ Hinsberg reagent
$III.$ Alkyl Diazonium salts	$C.$ Dyes
$IV.$ Aryl Diazonium salts	$D.$ Conversion to alcohols

Benzyl isocyanide can be obtained from which of the following reactions? Choose the correct answer from the options given below:
$A$. Benzyl bromide + $AgCN$
$B$. Benzylamine + $CHCl_3$ + $Aq. NaOH$
$C$. Bromobenzene + $AgCN$
$D$. Aniline + $CHCl_3$ + $Aq. NaOH$
$E$. $2-$Phenylethyl bromide + $KCN$

Similar Questions

The ammonolysis of alcohol is represented by the reaction $xCH_3OH + yNH_3 \xrightarrow[Al_2O_3/ThO_2]{300-400^{\circ}C} \text{Products}$. The products formed are:

An aromatic compound $A$ on treatment with aqueous ammonia and heating forms compound $B$,which on heating with $Br_2$ and $KOH$ forms a compound $C$ of molecular formula $C_6H_7N$. Write the structures and $IUPAC$ names of compounds $A, B$,and $C$.

Match the compounds given in List-$I$ with the items given in List-$II$.

List-$I$ List-$II$

$I.$ Benzenesulphonyl Chloride $A.$ Zwitterion

$II.$ Sulphanilic acid $B.$ Hinsberg reagent

$III.$ Alkyl Diazonium salts $C.$ Dyes

$IV.$ Aryl Diazonium salts $D.$ Conversion to alcohols

Consider the above sequence of reactions. The number of bromine atom$(s)$ in the final product $(P)$ will be:

Give a plausible explanation for each of the following:
$(i)$ Why are amines less acidic than alcohols of comparable molecular masses?
$(ii)$ Why do primary amines have higher boiling points than tertiary amines?
$(iii)$ Why are aliphatic amines stronger bases than aromatic amines?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Benzyl isocyanide can be obtained from which of the following reactions? Choose the correct answer from the options given below:$A$. Benzyl bromide + $AgCN$$B$. Benzylamine + $CHCl_3$ + $Aq. NaOH$$C$. Bromobenzene + $AgCN$$D$. Aniline + $CHCl_3$ + $Aq. NaOH$$E$. $2-$Phenylethyl bromide + $KCN$