Blocks A and B of mass 2,kg and 4,kg are susp | vedclass

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(A) The elevator is moving downward with an acceleration $a = 2\,m/s^2$. In the frame of the elevator,the effective acceleration due to gravity is $g_

Vedclass · Accepted Answer

$\frac{64}{3}\,N$

Vedclass · Answer

(A) The elevator is moving downward with an acceleration $a = 2\,m/s^2$. In the frame of the elevator,the effective acceleration due to gravity is $g_{eff} = g - a$. Taking $g = 10\,m/s^2$,we get $g_{eff} = 10 - 2 = 8\,m/s^2$. The tension $T$ in a string connecting two masses $m_1$ and $m_2$ over a pulley is given by the formula $T = \frac{2 m_1 m_2}{m_1 + m_2} g_{eff}$. Substituting the given values $m_1 = 2\,kg$,$m_2 = 4\,kg$,and $g_{eff} = 8\,m/s^2$: $T = \frac{2 	imes 2 	imes 4}{2 + 4} 	imes 8 = \frac{16}{6} 	imes 8 = \frac{8}{3} 	imes 8 = \frac{64}{3}\,N$.

Blocks $A$ and $B$ of mass $2\,kg$ and $4\,kg$ are suspended through a string using a pulley,inside an elevator moving downward with a constant acceleration of $2\,m/s^2$. Find the tension in the string connecting the two blocks.

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