Blood velocity: The flow of blood in a large | vedclass

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(C) Using Bernoulli's equation for a horizontal Venturi meter: $P_1 - P_2 = \frac{1}{2} \rho v_1^2 \left[ \left( \frac{A}{a} \right)^2 - 1 \right]$.Gi

Vedclass · Accepted Answer

$0.123$

Vedclass · Answer

(C) Using Bernoulli's equation for a horizontal Venturi meter: $P_1 - P_2 = \frac{1}{2} ho v_1^2 \left[ \left( \frac{A}{a} ight)^2 - 1 ight]$.Given: Pressure drop $\Delta P = 24 \; Pa$,density of blood $ho = 1.06 	imes 10^3 \; kg/m^3$,$A = 8 \; mm^2$,$a = 4 \; mm^2$.The ratio of areas is $\frac{A}{a} = \frac{8}{4} = 2$.Substituting the values into the equation:$24 = \frac{1}{2} 	imes 1060 	imes v_1^2 	imes (2^2 - 1)$$24 = 530 	imes v_1^2 	imes 3$$24 = 1590 	imes v_1^2$$v_1^2 = \frac{24}{1590} \approx 0.01509$$v_1 = \sqrt{0.01509} \approx 0.123 \; m/s$.

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