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(B) The total number of electrons in a $C_2$ molecule is $12$ $(6 + 6)$.According to Molecular Orbital Theory,the electronic configuration of $C_2$ is

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$2$

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(B) The total number of electrons in a $C_2$ molecule is $12$ $(6 + 6)$.According to Molecular Orbital Theory,the electronic configuration of $C_2$ is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2 = \pi 2p_y^2$.Bond order is calculated as: $	ext{Bond Order} = \frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons and $N_a$ is the number of antibonding electrons.Here,$N_b = 8$ and $N_a = 4$.$	ext{Bond Order} = \frac{8 - 4}{2} = \frac{4}{2} = 2$.

Bond order of $C_2$ vapour is :

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