Borazine,also known as inorganic benzene,can be prepared by the reaction of $3$ equivalents of "$X$" with $6$ equivalents of "$Y$". "$X$" and "$Y$",respectively,are:
- A$B(OH)_3$ and $NH_3$
- B$B_2H_6$ and $NH_3$
- C$B_2H_6$ and $HN_3$
- D$NH_3$ and $B_2O_3$
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Explain the following:
$(1)$ Aluminum forms $[AlF_6]^{3-}$ ion but boron does not form $[BF_6]^{3-}$ ion.
$(2)$ $PbX_2$ is more stable than $PbX_4$.
$(1)$ Aluminum forms $[AlF_6]^{3-}$ ion but boron does not form $[BF_6]^{3-}$ ion.
$(2)$ $PbX_2$ is more stable than $PbX_4$.
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