Boric acid is solid,whereas $BF_3$ is gas at room temperature because of
- AStrong ionic bond in Boric acid
- BStrong van der Waal's interaction in Boric acid
- CStrong hydrogen bond in Boric acid
- DStrong covalent bond in $BF_3$
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Statement-$1$: Orthoboric acid acts as a weak monobasic acid in water.
Statement-$2$: Orthoboric acid acts as a proton donor in water.
Statement-$2$: Orthoboric acid acts as a proton donor in water.
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View SolutionMatch Column-$I$ with Column-$II$ :
Column-$I$ Column-$II$ $A$. $Bi^{+3} \to (BiO)^{+}$ $P$. Heat $B$. $[AlO_2]^{-} \to Al(OH)_3$ $Q$. Hydrolysis $C$. $SiO_4^{-4} \to Si_2O_7^{-6}$ $R$. Acidification $D$. $(B_4O_7)^{-2} \to [B(OH)_3]$ $S$. Dilution with water
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| $A$. $Bi^{+3} \to (BiO)^{+}$ | $P$. Heat |
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| $C$. $SiO_4^{-4} \to Si_2O_7^{-6}$ | $R$. Acidification |
| $D$. $(B_4O_7)^{-2} \to [B(OH)_3]$ | $S$. Dilution with water |
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