Both $[Ni(CO)_4]$ and $[Ni(CN)_4]^{2-}$ are diamagnetic. The hybridization of nickel in these complexes,respectively,are

  • A
    $sp^3, sp^3$
  • B
    $dsp^2, sp^3$
  • C
    $sp^3, dsp^2$
  • D
    $dsp^2, dsp^2$

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Similar Questions

Identify the $CORRECT$ set of details from the following:
$A$. $[Co(NH_{3})_{6}]^{3+}$: Inner orbital complex; $d^{2}sp^{3}$ hybridized
$B$. $[MnCl_{6}]^{3-}$: Outer orbital complex; $sp^{3}d^{2}$ hybridized
$C$. $[CoF_{6}]^{3-}$: Outer orbital complex; $d^{2}sp^{3}$ hybridized
$D$. $[FeF_{6}]^{3-}$: Outer orbital complex; $sp^{3}d^{2}$ hybridized
$E$. $[Ni(CN)_{4}]^{2-}$: Inner orbital complex; $sp^{3}$ hybridized
Choose the correct answer from the options given below:

Which of the following complexes is paramagnetic and an inner orbital complex?

In an octahedral structure,the pair of $d$ orbitals involved in ${d^2}sp^3$ hybridization is

For the complexes showing the square pyramidal structure,the $d-$orbital involved in the hybridisation is

Which one of the following is an inner orbital complex?

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