Both the blocks shown in the figure have mass | vedclass

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(B) Let $T$ be the tension in the string and $F$ be the constant resistive force acting on each block.Since both blocks are moving with constant veloc

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$mg/2$

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(B) Let $T$ be the tension in the string and $F$ be the constant resistive force acting on each block.Since both blocks are moving with constant velocity,their acceleration is zero $(a = 0)$.For block $A$ (on the horizontal surface),the forces acting in the horizontal direction are tension $T$ (forward) and resistive force $F$ (backward). Applying Newton's second law: $T - F = 0$,which implies $T = F$.For block $B$ (hanging vertically),the forces acting are gravity $mg$ (downward),tension $T$ (upward),and resistive force $F$ (upward,as it opposes the downward velocity). Applying Newton's second law: $mg - T - F = 0$.Substituting $T = F$ into the second equation: $mg - T - T = 0$,which gives $mg - 2T = 0$.Therefore,$2T = mg$,or $T = mg/2$.

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