Bottles containing C_6H_5I and C_6H_5CH_2I lo | vedclass

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Question

(A) $C_6H_5I$ is an aryl halide where the $C-I$ bond has partial double bond character due to resonance,making it resistant to nucleophilic substituti

Vedclass · Accepted Answer

$A$ was $C_6H_5I$

Vedclass · Answer

(A) $C_6H_5I$ is an aryl halide where the $C-I$ bond has partial double bond character due to resonance,making it resistant to nucleophilic substitution under these conditions. Thus,it does not release $I^-$ ions to form a yellow precipitate of $AgI$ with $AgNO_3$.$C_6H_5CH_2I$ is a primary alkyl halide (benzyl iodide) which undergoes nucleophilic substitution with $NaOH$ to form $C_6H_5CH_2OH$ and $NaI$. The $NaI$ dissociates to provide $I^-$ ions,which react with $AgNO_3$ to form a yellow precipitate of $AgI$.Since $B$ gave a yellow precipitate,$B$ must be $C_6H_5CH_2I$,and $A$ must be $C_6H_5I$.Therefore,the statement '$A$ was $C_6H_5I$' is true.

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