Box A contains 25 slips of which 19 are marke | vedclass

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(D) Total number of slips in the third box,$n(S) = 25 + 50 = 75$.From the given information:Number of slips marked $Rs. 1$ in Box $A = 19$.Number of s

Vedclass · Accepted Answer

$\frac{11}{75}$

Vedclass · Answer

(D) Total number of slips in the third box,$n(S) = 25 + 50 = 75$.From the given information:Number of slips marked $Rs. 1$ in Box $A = 19$.Number of slips marked $Rs. 5$ in Box $A = 25 - 19 = 6$.Number of slips marked $Rs. 1$ in Box $B = 45$.Number of slips marked $Rs. 13$ in Box $B = 50 - 45 = 5$.Total number of slips marked other than $Rs. 1 = 6 + 5 = 11$.Therefore,the required probability $= \frac{	ext{Number of slips marked other than } Rs. 1}{	ext{Total number of slips}} = \frac{11}{75}$.

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