Box $A$ contains $2$ black and $3$ red balls,while Box $B$ contains $3$ black and $4$ red balls. Out of these two boxes,one is selected at random; and the probability of choosing Box $A$ is double that of Box $B$. If a red ball is drawn from the selected box,then the probability that it has come from Box $B$ is:

  • A
    $\frac{21}{41}$
  • B
    $\frac{10}{31}$
  • C
    $\frac{12}{31}$
  • D
    $\frac{13}{41}$

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