Bromine trifluoride autoionizes to form BrF_2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For $BrF_2^+$: The central $Br$ atom has $7$ valence electrons. It forms $2$ bonds with $F$ atoms and loses $1$ electron to become a cation, leavi

Vedclass · Accepted Answer

bent, square planar

Vedclass · Answer

(A) For $BrF_2^+$: The central $Br$ atom has $7$ valence electrons. It forms $2$ bonds with $F$ atoms and loses $1$ electron to become a cation, leaving $3$ lone pairs. However, considering $VSEPR$ theory for $AX_2E_2$ type (where $X=2$ bonding pairs and $E=2$ lone pairs), the geometry is bent.For $BrF_4^-$: The central $Br$ atom has $7$ valence electrons, gains $1$ electron from the anion formation, and forms $4$ bonds with $F$ atoms, leaving $2$ lone pairs. This corresponds to $AX_4E_2$ type, which results in a square planar structure.

List-$I$ (Shape)	List-$II$ (Molecules)
$A$. $T$-shaped	$I$. $XeF_4$
$B$. Trigonal planar	$II$. $SF_4$
$C$. Square planar	$III$. $ClF_3$
$D$. See-saw	$IV$. $BF_3$

Bromine trifluoride autoionizes to form $BrF_2^+$ and $BrF_4^-$. The shapes of the cation and anion are respectively . . . . . . ,and . . . . . . .

Similar Questions

What is bond angle? Explain.

In $ICl_{4}^{-}$,the shape is square planar. The number of bond pair-lone pair repulsions at $90^{o}$ are

The number of bond pairs,lone pairs present on the central atom of $SF_4$ molecule and its shape respectively are

The bond angle in a water molecule is nearly or directed bonds in water form an angle of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module